Problem
Write the slope-intercept form of the line described in the following:
Parallel to 4x + 5y=20
and passing through (12,4)
Solution>
For this case we need to have the same slope, and if we write the equation given we see:
5y = 20 -4x
y = 4 -4/5 x
then the slope m = -4/5
and we also know a point given x= 12, y= 4 and we can do the following:
4 = -4/5 (12) +b
4 = -48/5 + b
And if we solve for the intercept we got:
b= 4 +48/5= -28/5
And our equation would be given by:
y = -4/5 x -28/5
I think this is what you are looking for:
=−12
a
b
=
−
12
+=4
a
+
b
=
4
(+)2=42
(
a
+
b
)
2
=
4
2
2+2+2=16
a
2
+
b
2
+
2
a
b
=
16
∴2+2=16+2×12=40
∴
a
2
+
b
2
=
16
+
2
×
12
=
40
Now, (−)2=2+2−2=40+2×12=64
(
a
−
b
)
2
=
a
2
+
b
2
−
2
a
b
=
40
+
2
×
12
=
64
∴(−)=64‾‾‾√=±8
∴
(
a
−
b
)
=
64
=
±
8
So, 2−2=(+)(−)
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
2−2=(4)(±8)=±32
a
2
−
b
2
=
(
4
)
(
±
8
)
=
±
32
Hope that helps and sorry if it is confusing!
A’(-8,-4) B’(4,-4) C’(4,8) D’(-8,8)
Because the scale factor is 4 all you do is multiply your coordinates by 4
Answer:
are you ok?
Step-by-step explanation:
why did you need help lol
