Answer:
7
Step-by-step explanation:
1 ) Reflex AOB = 290°
2 ) x = 30°
2x = 2 × 30° = 60° and 3x = 3 × 30° = 90°
3 ) k = 48°
~ nightmare 5474~
Answer:
It must be the cost of the one table.
Step-by-step explanation:
It's logic. 25x is the cost of the (unknown) number of chairs.
The total Amount he spent is the cost of the chairs <u>plus</u> what he spent on the table.
I think of these in terms of "short side", "long side" and "hypotenuse." The proportions will be true that equate the ratios of corresponding sides.
I is (long side of CDB)/(short side of CDB) = (long side of BDA)/(short side of BDA)
These are corresponding sides, so the proportion is <em>true</em>.
II is (hypotenuse of CBA)/(long side of CBA) = (long side of CBA)/(hypotenuse of CBA)
This proportion equates a value to its inverse, so is <em>false</em> (since the triangle has non-zero area)
III is (long side of CBA)/(short side of CBA) = (hypotenuse of CBD)/(long side of CBD)
The sides involved here are not corresponding, so this is <em>false</em>.
IV is (long side of CDB)/(hypotenuse of CDB)/(long side of BDA)/(hypotenuse of BDA)
These are corresponding sides, so the proportion is <em>true</em>.
The appropriate choice is ...
... a. I and IV only
Answer:
p = 6/11.
Step-by-step explanation:
So we have a bag that contains 6 red marbles and 6 green marbles.
Then the total number of marbles that are in that bag is:
6 + 6 = 12
There are 12 marbles in the bag, and we assume that all marbles have the same probability of being randomly drawn.
Now we draw two marbles, we want to find the probability that one is red and the other is green.
The first marble that we draw does not matter, as we just want the second marble to be of the other color.
So, suppose we draw a green one in the first attempt.
Then in the second draw, we need to get a red one.
The probability of drawing a red one will be equal to the quotient between the red marbles in the bag (6) and the total number of marbles in the bag (12 - 1 = 11, because one green marble was drawn already)
Then the probability is:
p = 6/11.
Notice that would be the exact same case if the first marble was red.
Then we can conclude that the probability of getting two marbles of different colors is:
p = 6/11.