So to make an inequality, and we let c=number of coins then:
c≥6
Answer: 8(8u-5)
Step-by-step explanation:
Find a number that goes into both 64 and 40 the GCF of both is 8 so 8 goes on the outside of the new factor 8u-5 because if we distribute back we should arrive at the original equation
8(8u-5)
Answer:
3a^2 - 6b + 2ab
Step-by-step explanation:
Put all the like terms together
(4a^2 - a^2) - (7b + b) + 2ab
then simplify
(4a^2 - a^2) = 3a^2
(-7b + b) = -6b
then rewrite
3a^2 - 6b + 2ab
