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USPshnik [31]
3 years ago
9

Can anyone help me with this?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

-37z

Step-by-step explanation:

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Use the Substitution Method, what is the point of intersection for the following system:
Wittaler [7]

Answer:

2x + 2(x - 3) = 18 \\ 2x + 2x - 6 = 18 \\ 4x = 24 \\ x = 24 \div 4 = 6 \\ y = x - 3 = 6 - 3 = 3

8 0
2 years ago
Simplify 7+5−15()−(−3) =
DENIUS [597]

Answer:

0

Step-by-step explanation:

7 + 5 - 15 -(-3)

=> 12 - 15 + 3

=> 12 - 12

=> 0

4 0
2 years ago
Please help me!!!!!!!!!!
PolarNik [594]
Just divide the arc the inscribe angle forms by 2.  So 100/2 = 50 = a, and b is 55.
4 0
3 years ago
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Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
John owns a hot dog stand. He has found that his profit is represented by the equation p(x)=-x^2+62x+77, with p being profits an
dedylja [7]
Using a graphing calculator you can find that the maximum is 1038, so the profit starts to decline at the t value for <span>1038</span>, which is 31


4 0
3 years ago
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