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Mila [183]
3 years ago
6

(50 POINTS) Math Inverse Functions please help

Mathematics
2 answers:
liq [111]3 years ago
8 0

Answer:

inverse of ordered pair (1,3),(7,4),(8,6)and (9,y)

is (3,1),(4,7),(6,8)and(y,9)

restriction is

y≠3,4&8

Afina-wow [57]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

An inverse function has the x and y coordinates switched. For example, if a function has point (1, 3), then the inverse function has point (3, 1).

Let's find the ordered pairs of the inverse function. We take all the ordered pairs of the original function:

(1, 3), (7, 4), (8, 6), (9, y)

Now we switch x and y in each ordered pair to come up with the inverse function.

The inverse function has these ordered pairs:

(3, 1), (4, 7), (6, 8), (y, 9)

For a relation to be a function, a value used as an x-coordinate can appear only once.

The last ordered pair is (y, 9). For the inverse relation to be a function, y cannot be 3, 4, or 6.

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What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D
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Answer:

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Step-by-step explanation:

\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a}  \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a}  = \frac{-6-14}{2}=\frac{-20}{2} = -10

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Read 2 more answers
Can someone get this? Ive been trying and cant get it
Dmitry [639]

<u>Given</u><u> </u><u>:</u><u>-</u>

  • The roots of the function are 5 and -3 .

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The Quadratic function .

<u>Answer</u><u> </u><u>:</u><u>-</u>

The roots of the function are 5 and -3 . In general we can write the Quadratic function with roots π and ∆ as ,

\sf\longrightarrow f(x) = ( x - π )(x-∆)

So on using this we have ,

\sf\longrightarrow f(x) = ( x -5)( x -(-3))

\sf\longrightarrow f(x) = (x-5)(x+3)

\sf\longrightarrow f(x) = x(x-5)+3(x-5)

\sf\longrightarrow f(x) = x² -5x +3x -15

\sf\longrightarrow f(x) = x² -2x -15

<u>Hence </u><u>the</u><u> required</u><u> </u><u>answer</u><u> </u><u>is </u><u>x²</u><u> </u><u>-2x </u><u>-</u><u>1</u><u>5</u><u>.</u>

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2 years ago
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