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just olya [345]
3 years ago
7

Can someone pls pls help me on this question !!!!!

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

c. y= 0.5(2)^x

Step-by-step explanation:

i hope this helps :)

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\large -6x+6y=6<br> \large 6x+3y=12
Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1)  = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0
3 years ago
What is 2x+3+8x=3x+9x+7
Reika [66]

Answer:

x=-2

Step-by-step explanation:

Hey there!

In order to solve this equation, you need to combine like terms

The equation after combining the x terms and the contants will look like this

10x+3=12x+7

Now you have to take 10x away from both sides

3=2x+7

Now bring all the constants to the left side

3-7=2x

Simplify

-4=2x

divide 2 on both sides to get x by itself

x=-2

So, the answer is x=-2

3 0
3 years ago
Can someone help my little sister with her quiz? She gotta have it turned in by midnight!! So we need answers asap!!
fiasKO [112]
I’m pretty sure it’s the first one cause it’s half of the 6 blocks
4 0
3 years ago
Read 2 more answers
4+3(2r+2s)+3r<br><br> Simplify this expression
Ipatiy [6.2K]
Hello!

First you can distribute the 3

4 + 6r + 6s + 3r

Then you combine like terms

4 + 9r + 6s

The answer is 9r + 6s + 4

Hope this helps!
3 0
3 years ago
Find the general solution of the given differential equation. cos^2(x)sin(x)dy/dx+(cos^3(x))y=1 g
eimsori [14]

If the given differential equation is

\cos^2(x) \sin(x) \dfrac{dy}{dx} + \cos^3(x) y = 1

then multiply both sides by \frac1{\cos^2(x)} :

\sin(x) \dfrac{dy}{dx} + \cos(x) y = \sec^2(x)

The left side is the derivative of a product,

\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)

Integrate both sides with respect to x, recalling that \frac{d}{dx}\tan(x) = \sec^2(x) :

\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx

\sin(x) y = \tan(x) + C

Solve for y :

\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}.

7 0
2 years ago
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