By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
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Answer :
Step-by-step explanation :
To find the product of
First we expand the bracket ,
it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.
Hence
we now apply the law of indices
meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.
Then, simplify to obtain
Answer:
x=811/238, y=36/119. (811/238, 36/119).
Step-by-step explanation:
4x+(x-y/8)=17
2y+x-(5y+2/4)=2
-----------------------
4x+x-y/8=17
5x-y/8=17
40x-y=136
y=40x-136
------------------
2y+x-5y-2/4=2
2y-5y+x-1/2=2
-3y+x=2+1/2
-3y+x=4/2+1/2
-3y+x=5/2
-3(40x-136)+x=5/2
-120x+408+x=5/2
-119x=5/2-408
-119x=5/2-816/2
-119x=-811/2
119x=811/2
x=(811/2)/119
x=(811/2)(1/119)=811/238
y=40(811/238)-136
y=16220/119-136
y=36/119
x=811/238, y=36/119.
Answer:
(7,6)
Step-by-step explanation:
rotate 90 degree clockwise: (x,y) -> (y,-x)
There are 32 nickels and 112 dimes. Hope this helps.
