All categories

2 years ago

If f(x) = 5x^2 -13 and g(x) =8x^3 +4, find (f+g)(x)

Mathematics

2 answers:

salantis [7]2 years ago

8 0

<h3>Given:</h3>

f(x) = 5x^2 - 13

g(x) = 8x^3 + 4

The value of (f+g)(x) or <u>f(x) + g(x)</u> .

<h3>Explanation:</h3>

By putting the respected values, we get

f(x) + g(x) = 5x^2 - 13 + 8x^3 + 4

By simplifying the like terms, we get

<u>f(x) + g(x) = 8x^3 + 5x^2 - 9</u>

<h2>Answer:</h2>

<u>(f+g)(x) = 8x^3 + 5x^2 - 9</u>

Dmitry [639]2 years ago

5 0

Answer:

(f+g)(x) = 8x^3 + 5x^2 - 9

Step-by-step explanation:

<h3>Given</h3>

f(x) = 5x^2 -13 and g(x) =8x^3 +4

(f+g)(x)

<h3>Solution</h3>

(f+g)(x) =
f(x) + g(x) =
5x^2 -13 + 8x^3 +4 =
8x^3 + 5x^2 - 9

You might be interested in

A rectangular prism has a length of 14 feet, a height of 11 feet, and a width of 13 feet. What is its volume, in cubic feet ?

Radda [10]

2002 ft^3. Hope this is right!

4 0

2 years ago

Sandy is working with a carpenter to frame a house. They are using 8-foot-long boards, but each board must be cut to be 7 feet i

Tju [1.3M]

Answer:

5/4in

Step-by-step explanation:

The initial length:

1 ft = 12 in

8 ft = 8 * 12 in

= 96 in

The final length:

7 ft 10 3/4 in = 7 ft + 10 in + 3/4 in

= 7 * 12 in + 10 in + 3/4 in

= 84 in + 10 in + 3/4 in

= 94 in + 3/4 in

The final length:

96 in - 94 in - 3/4 in = 2 in - 3/4 in = 8/4 in - 3/4 in = 5/4 in

8 0

3 years ago

Help me pleaseeeeeeeeeeee

zavuch27 [327]

O.6 easy because of the answer that is why

4 0

2 years ago

. Write the equation of a line in the graph below.

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

The y intercept is (0,2) so you can eliminate A and C because they have -2 and the slope is negative so you can eliminate B because it has a slope of +3 so you are left with D.

4 0

3 years ago

Read 2 more answers

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

<u><em>Final answer:-</em></u>

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

2 years ago