Question

What is the value of x, when x2 + 5 = 21?

Answer 1

Hey there!

• $\bold{x^2+5=21}$
• Firstly, subtract by the number $\bold{5}$  on each of your sides
• $\bold{x^2+5-5=21-5}$
• $\bold{Cancel:5-5}$ because it gives us the result of $\bold{1}$
• $\bold{Keep:21-5}$  because it equals: $\bold{16}$
• $\bold{x^2=16}$
• Nextly, we have to take our square root
• $\bold{x=}$±$\bold{\sqrt{16}}$
• Solve the square root and you have found your answer
• $\boxed{\boxed{\bold{Answer:x=4[or]x=-4}}}$ $\bold{\checkmark}$

Good luck on your assignment and enjoy your day!

~$\bold{LoveYourselfFirst:)}$