The graph below shows Ariana's pay as a painter. How much does Ariana charge per painting?

Use the distributive property to expand each expression. 0.5(12m - 22n) 0.5(12m - 22n =0.5(____) - 0.5(____)

lesya [120]

Answer:

0.5(_12m_) - 0.5(_22n_)

Step-by-step explanation:

To apply the distributive property multiply each the term outside to each term in the parenthesis.

0.5(12m - 22n) 0.5(12m - 22n =0.5(_12m_) - 0.5(_22n_)

5 0

3 years ago

Trying to understand this question

Varvara68 [4.7K]

Answer:

option 2 I think sorry if its incorrect

5 0

3 years ago

What is the discrimination of the quadratic equation 6x^2-9x-8=0

aleksklad [387]

Answer:

first setup your problem. it should look like this :

6 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

What's are the factors of 60a

polet [3.4K]

Question D:

The terms in the expression are '60a' and '30c'

Question E:

Factors of 60a could be

2 × 30 × a
3 × 20 × a
4 × 15 × a
5 × 12 × a
6 × 10 × a

Question F

Factors of 30c could be
2 × 15 × c
3 × 10 × c
5 × 6 × c

Question G

Coefficient of 60a is '60'
Coefficient of 30c is '30'

Question H

The meaning of the two terms

Term '60a' means multiply the value of 'a' by 60 to find the total cost for 'a' number of adults

Term '30c' means multiply the value of 'c' by 30 to find the total cost for 'c' number of children

3 0

3 years ago