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Paha777 [63]
2 years ago
6

The lengths of two sides of a triangle are given. Find the range of possible lengths for the third side.

Mathematics
1 answer:
Sladkaya [172]2 years ago
6 0

Answer:

0 < x < 12

Step-by-step explanation:

According to the triangle inequality theorem, the sum of the two sides must be greater than the length of the third side. 6+6 = 12

0 < x < 12

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Erin is 8 years younger than twice Paula’s age. The sum of their ages is 40. How old is Erin
Lina20 [59]
You do the sum(40) subtracted by 8, the answer from that divided by 2 since Erin's two times younger.
40-8=32
32÷2=16
Then if you want to check it you do the opposite and get the same sum(40) so 16×2=32 and 32+8=40
6 0
3 years ago
A cube made out of lead has a mass of 12 grams. A side of the cube has length 1 cm. What would be the mass of the cube whose sid
Ulleksa [173]

Answer:

<h3><em><u>The mass of a lead cube whose </u></em><em><u>side </u></em><em><u>have length 1.5 cm is 40.5 </u></em><em><u>grams</u></em></h3>

Step-by-step explanation:

<u>1. Let's review the information given to</u>

<u>1. Let's review the information given tous to answer the question correctly:</u>

<u>1. Let's review the information given tous to answer the question correctly:Mass of the cube made out of lead</u> = 12

= 12grams

Side of the cube <em>= 1 cm</em>

2. <em><u>What would be the mass of a lead</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let's</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube and</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube andthen its density, this way:</u></em>

<h3>Volume = Height* Width * Length</h3><h3>Volume=1*1*1</h3><h3>Volume =1 cm</h3>

Let's recall the formula of the density:

Density Mass/Volume, therefore:

Density of the lead <em><u>= 12/1= 12 gr/</u></em><em><u>cm</u></em>

<em><u>Now, let's calculate the volume of the</u></em>

<em><u>Now, let's calculate the volume of thesecond cube:</u></em>

<h3><em>Volume = Height Width Length</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5Volume =3.375 cm3</em></h3>

<u>Finally, let's calculate the mass, using</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we already</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we alreadyknow:</u>

<h3>Density = Mass/Volume</h3><h3><em>12 Mass/3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375Mass = 40.5 gramss</em></h3>
8 0
2 years ago
Round each number to the nearest ten.
Bezzdna [24]
552.17 rounds to 550
48.35 rounds to 50
550-50=500
5 0
3 years ago
What is the answer and how do you do the following <br> p2 +14p +24
lesya692 [45]

Answer:

hope that helps

Step-by-step explanation:

Factoring p2-14p-24

The first term is, p2 its coefficient is 1 .

The middle term is, -14p its coefficient is -14 .

The last term, "the constant", is -24

Step-1 : Multiply the coefficient of the first term by the constant 1 • -24 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -14 .

-24 + 1 = -23

-12 + 2 = -10

-8 + 3 = -5

-6 + 4 = -2

-4 + 6 = 2

-3 + 8 = 5

-2 + 12 = 10

-1 + 24 = 23

8 0
3 years ago
Read 2 more answers
Hello I’m trying to solve this problem I just don’t know how to do it.
Katyanochek1 [597]

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

3 0
3 years ago
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