If you ever have a polynomial with a solution of bi, then it will also have a solution of -bi. Imaginary solutions always come in pairs.
So, yes, you could have a polynomial with solutions 2i and 5i, as long as -2i and -5i are also solutions.
(x-2i)(x+2i)(x-5i)(x+5i) would be the most basic polynomial you could form.
(x-2i)(x+2i)(x-5i)(x+5i) = (x^2+4)(x^2+25)
= x^4 + 29x^2 + 100
So the equation would be x^4 + 29x^2 + 100 = 0.
Now, if the question was "only the solutions of 2i and 5i and no others," then the answer is no, for the previously stated reason.
Answer:
Option 2: AAS is the right answer
Step-by-step explanation:
In the diagram, two triangles are given with two angle measurements and one non-included side.
It can also be seen that the respective angles of both triangles have same measurement and the non-included side is also congruent.
AAS Postulate:
"AAS postulate states that when two angles and one excluded side are congruent in two triangles then the triangles are congruent."
Hence,
Option 2: AAS is the right answer
Answer:
141 km
Step-by-step explanation:
This is because as the boat travels at a constant speed, it will travel the same distance each hour. The boat travels at 35.25 km/h, so you must multiply this number by 4.
This gets the answer 141 km.
