P/4 + pq when p= 8 and q= 6

Mathematics

1 answer:

777dan777 [17]2 years ago

4 0

The answer is 50!!!!

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In △ABC , m∠A=53°,m∠B=17°, and a=27. Find the perimeter of the triangle.

sdas [7]

Using the Law of Sines (sinA/a=sinB/b=sinC/c) and the fact that all triangles have a sum of 180° for their angles.

The third angle is C is 180-53-17=110°

27/sin53=b/sin17=c/sin110

b=27sin17/sin53, c=27sin110/sin53

And the perimeter is a+b+c so

p=27+27sin17/sin53+27sin110/sin53 units

p≈68.65 units (to nearest hundredth of a unit)

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3 years ago

Describe the location of the point having the following coordinates. negative abscissa, zero ordinate between Quadrant II and Qu

Marianna [84]

Answer:

The location of the point is between Quadrant II and Quadrant III

Step-by-step explanation:

we know that

The abscissa refers to the x-axis and ordinate refers to the y-axis

in this problem we have

the coordinates of the point are $(-x,0)$