A is the correct answer
good luck
Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
It would be to little because it would only be 30 cents
Question:
Find the gradient of the line passing through (6,8) and (4,10).
Answer:
-1 is the right answer.
Step-by-step explanation:
Slope of the line = The gradient of the line
Gradient of the line is known as change in the value of y-axis by change in the value of x-axis
Gradient = ∆y\∆x

The answer would be -18 and 3