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Karo-lina-s [1.5K]
2 years ago
6

The case of a rectangular electronic tablet has an area of A square inches. The length of the case is 12.5 in. Which equation re

presents h, the height of the case in inches?
Mathematics
2 answers:
Alex Ar [27]2 years ago
7 0

Answer:

A/12.5=h

Step-by-step explanation:

A is 12.5 x h so you do inverse to work out height

Marizza181 [45]2 years ago
3 0

Answer:

A/12.5=h

Step-by-step explanation:

A is 12.5 x h so you do inverse to work out height

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Is y=4x+6 And -8x+2y=12 independent dependent or inconsistent
FromTheMoon [43]
I hope this helps you



-8x+2. (4x+6)@=12



-8x+8x+12=12


12=12


0=0
6 0
3 years ago
What is the slope - intercept form equation of the line graphed below ?
Jlenok [28]
Slope = (7-2)/(3-0) = 5/3

slope intercept b = 2

equation y= 5/3x +b

<span>answer: B. y=5/3x + 2 </span>
7 0
3 years ago
In a complete paragraph, explain how to scope a speech. <br> Please use your own words.
butalik [34]

Answer:

Prepare. You dread public speaking because you don't know what to say.

Psych yourself. ...

Know your audience. ...

Be an expert on your topic. ...

Visualize. ...

Conduct an ocular inspection. ...

Read, watch, and listen to good speakers.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The length of a flower garden is 9 meters. The width of the garden, w, is unknown. If the area of the garden is greater
muminat

Answer:

The width should be more than 5 m. So it can be  6,7 ...

Step-by-step explanation:

The length of a flower garden is = 9 m

The width of a flower garden is   = w

The area of a flower garden > 45 sq. m

The area of a flower garden  = l * b

l * b > 45

9 * b > 45

the width should be more than 5 m. So it can be  6,7 ...

5 0
3 years ago
Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
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