Answer:
167.19
14.50 x 8 = 116.00
14.50 + 1.75 = 16.25 per hour overtime
16.25 × 3.15 hour overtime = 51.19
116.00 + 51.19 = 167.19
Step-by-step explanation:
Answer:
1/15
Step-by-step explanation:
4 × 1/6 × 1/10
reduce the numbers :
1/3 × 1/5
now multiplique the fractions
=1/15
First graph because when you solve you get -2 is greater than 8 then divide by negative two which will give you x is greater than 4 but since you divided by a negative you switch the sign so it’s x is less than -4
Answer:
Null hypothesis:![\mu \geq 6](https://tex.z-dn.net/?f=%5Cmu%20%5Cgeq%206)
Alternative hypothesis: ![\mu](https://tex.z-dn.net/?f=%20%5Cmu%20%3C6)
For this case after conduct the one lower tail test we got the following p value:
![p_v = P(t](https://tex.z-dn.net/?f=%20p_v%20%3D%20P%28t%20%3C-1.68%29%20%3D%200.0465)
And for this case if we want to conduct a bilateral test or two sided the sytem of hypothesis are:
Null hypothesis:![\mu = 6](https://tex.z-dn.net/?f=%5Cmu%20%3D%206)
Alternative hypothesis: ![\mu \neq 6](https://tex.z-dn.net/?f=%20%5Cmu%20%5Cneq%206)
And for this case the p value can be calculated like this:
![p_v = 2* P(t](https://tex.z-dn.net/?f=%20p_v%20%3D%202%2A%20P%28t%20%3C-1.68%29%20%3D2%2A%200.0465%3D%200.0930)
Step-by-step explanation:
For this case we are trying to proof the following system of hypothesis:
Null hypothesis:![\mu \geq 6](https://tex.z-dn.net/?f=%5Cmu%20%5Cgeq%206)
Alternative hypothesis: ![\mu](https://tex.z-dn.net/?f=%20%5Cmu%20%3C6)
For this case after conduct the one lower tail test we got the following p value:
![p_v = P(t](https://tex.z-dn.net/?f=%20p_v%20%3D%20P%28t%20%3C-1.68%29%20%3D%200.0465)
And for this case if we want to conduct a bilateral test or two sided the sytem of hypothesis are:
Null hypothesis:![\mu = 6](https://tex.z-dn.net/?f=%5Cmu%20%3D%206)
Alternative hypothesis: ![\mu \neq 6](https://tex.z-dn.net/?f=%20%5Cmu%20%5Cneq%206)
And for this case the p value can be calculated like this:
![p_v = 2* P(t](https://tex.z-dn.net/?f=%20p_v%20%3D%202%2A%20P%28t%20%3C-1.68%29%20%3D2%2A%200.0465%3D%200.0930)
The area of a circle is πr^2
Area formula for the white region is π6^2
π6^2 = 36π
Subtract the area of the white region from the combined area
100π - 36π = 64π