Question

A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softball's acceleration is –16 ft/s2, which quadratic equation models the situation correctly?

Answer 1

Answer:

The function is:

$f(t) = -16t^2 + 50t + 3$

Step-by-step explanation:

Given

$height = 3ft$

$velocity = 50ft/s$

$acceleration = -16ft/s^2$

Required

The function

Let t represents time;

So, we have:

$f(t) = acceleration * t^2 + velocity * t + height$

So, we have:

$f(t) = -16* t^2 + 50* t + 3$

$f(t) = -16t^2 + 50t + 3$