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Contact [7]
2 years ago
13

How to find the derivative of tanx​

Mathematics
1 answer:
prohojiy [21]2 years ago
8 0

Answer:The formula for differentiation of tan x is, d/dx (tan x) = sec2x (or) (tan x)' = sec2x.

Step-by-step explanation:

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To negatives equal a positive. Convert both of the mixed numbers into a improper fraction. Cross simplify 5 and 5, they both turn into one’s. Multiply and you should get 7/3 or 2 1/3.
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alan bought 3 pencils and a notebook. the notebook cost $6, and he spent a total of $12. how much did each pencil cost?
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Answer:

Step-by-step explanation:

3x+6=12

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Find the center and radius of this
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\text{Hello there! :)}

Answer:

\boxed{\text{Center at } (7, -4), \text{ Radius of } 7.}

\text{Formula for a circle: }  (x - h)^{2} + (y - k)^{2}  = r^{2}  \text{ Where:}

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h = 7\\\\k = -4\\\\r = \sqrt[]{49} = 7 \\\\\text{So:}

\text{Center at } (7, -4), \text{ Radius of } 7.

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A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
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18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

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