Given:
In circle O, m∠R = 30.8°.
To find:
The m∠NOQ
Solution:
Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.
Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.
Using central angle theorem, we get
Therefore, .
Answer:
I can not solve it in the system of the image, but i will give you the graph so you can copy it, or at least see how it is done.
First, we have the lines:
y = (1/3)*x + 6
y = (-5/3)*x - 6
To graph these lines, you must find two points for the lines and then draw a line that connects the points.
To do it, you can evaluate each line in two different values of x, for example for the first line we can have:
y(0) = (1/3)*0 + 6 = 6 (then we have the point (0, 6))
y(3) = (1/3)*3 + 6 = 7 (then we have the point (3, 7))
And for the second line, we will have:
y(0) = (-5/3)*0 - 6 = -6 (then we have the point (0, -6))
y(3) = -(5/3)*3 - 6 = -11 (then we have the point (-3, -11))
Now with those points we can graph the lines, and the solution of the system of equation will be the point where the two lines intersect.
The graphs of the lines are shown below:
Where the grey line is the first one, and the green is the second.
In the graph, you can see that the lines intersect in the point (-6, 4)
Then the solution for the system is x = -6, and y = 4.
