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2 years ago

A dinner plate has a circumference of 100.48 cm. What is the area of the dinner plate? Use 7 = 3.14.

Mathematics

1 answer:

kari74 [83]2 years ago

7 0

Answer:

803.84, or C.

Step-by-step explanation:

If we know the circumference then we can use that to find the radius!

(π =pi)

Area of a circle formula: π · r^2

Let us plug in the circumference into the formula (not the area formula, the circumference one!)

c=2πr

100.48=2πr - 2*3.14 =6.28

100.48=6.28r

divide both sides by 6.28!
r= 16

Now, we plug that in the area formula.

π · r^2

3.14 * 16^2

3.14 * 256 =

803.84

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Finger [1]

Step-by-step explanation:

2^3 X 3^-4 X 5^2 / (2x5)^2 X 2 X 3^2 X 3^-6

I will simply the expression on the RHS if the bracket first

2^2 X 5^2 X 2 X 3^2 X 3^-6

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3 years ago

There were 13,531 new products introduced last year. If 87% of the products introduced last year failed to reach their business

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I'm assuming that since 87% failed, that would the remaining 13% was a success. If that assumption is correct, than we simply have to take:

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3 years ago

Find the slope in (-2,8) and (1,6)

Salsk061 [2.6K]

Formula for slope: $\frac{y2 - y1}{x2 - x1}$

y₂: 6

y₁: 8

x₂: 1

x₁: -2

Plug them into the slope equation:

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The slope is $-\frac{2}{3}$ .

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3 years ago

Read 2 more answers

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$