Question

Find the intersection point between the lines of equations:2x-y+6=0 and 2x+3y-6=0 ​

Answer 1

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

$\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0$

On subtracting the given equations we have,

$\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3$

Put this value in any equation , we have ,

$\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5$

Hence the lines will Intersect at ,

$\implies\underline{\underline{ Point=(-1.5, 3)}}$

Answer 2

for the first one x = 1/2 y-3" and y = 2 x + 6 and for the other one is x =  − 3 /2  y+ 3  and y= − 2 /3  x + 2

how i did this Step 1: Add -3y to both sides.

Step 2: Add 6 to both sides.

Step 3: Divide both sides by 2.