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Alona [7]
2 years ago
11

PLEASEE HELP HURRYYYYYY PLEASE

Mathematics
1 answer:
olga2289 [7]2 years ago
5 0

Answer:

12.5

Step-by-step explanation:

We can use ratios to solve

4        4+6

---- = ----------

5         AC

4        10

---- = ----------

5         AC

Using cross products

4 * AC = 5*10

4AC = 50

Divide by 4

AC = 50/4

AC =12.5

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Solve for v <br> 4v=72<br> Simplify your answer as much as possible.
Ludmilka [50]
Answer:
v = 18

Explain:
Equation; 4v = 72

Begin by dividing both sides
by 4 and isolating the v
v = 18

hopefully this helps you with your problem!
(a brainliest would be appreciated)
5 0
3 years ago
Mr. Clifton was preparing for his upcoming birthday party. He ordered 51 white balloons and 47 red balloons. As he walked to his
Andrej [43]

Answer:

28 i think

Step-by-step explanation:

51+47=98

98-12 the ones that flew away that takes it to 86

86/3 the 3 balloons buntch than is 28

p.s. i mght of got some equations wrong but this is what i got

4 0
3 years ago
A bookstore manager marks down the price of older hardcover books, which originally sell for b dollars, by 52%.
mafiozo [28]

Complete question :

A bookstore manager marks down the price of older hardcover books, which originally sell for b dollars, by 52%.

a. Write the markdown as a decimal. b. Write an expression for the sale price of the hardcover book.

Answer:

0.52 ; 0.52b

Step-by-step explanation:

The markdown percentage = 52%

Expresaing markdown as a decimal :

52% = 52 / 100 = 0.52

Expression for the sale price of hardcover book:

Original price = b

Price was marked down by 0.52

Hence, sales price becomes ;

Original price * markdown

b * 0.52

0.52b

3 0
2 years ago
Yall I just realized I skipped 4 and 5- but here's question 4
natali 33 [55]
The sum of five and the quotient of two and four
because u do division first
8 0
2 years ago
Can i please get some (help on my maths)
quester [9]
ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}


We\ have:\\\\15x^2+7x-12=0\\\\a=15;\ b=7;\ c=-12\\\\substitute\\\\x_1=\dfrac{-7-\sqrt{7^2-4\cdot15\cdot(-12)}}{2\cdot15}=\dfrac{-7-\sqrt{49-5(15)(-12)}}{30}\\\\x_2=\dfrac{-7+\sqrt{49-4(15)(-12)}}{30}

First option.
5 0
3 years ago
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