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mina [271]
2 years ago
9

Mari has a part time job. She earns $7 an hour. She makes at most $143.50 per week. What is the greatest number of hours she wor

ks?
Mathematics
1 answer:
vichka [17]2 years ago
3 0

20.5 hours a week

$7  divided by $143.50 = 20.5 hours

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Demarcus has to wrap a gift for his friend's birthday party. the gift is in a rectangular box with the dimensions shown below. h
Leya [2.2K]

The gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².

<h3>What is the Total Surface Area of a Rectangular Box?</h3>

Total surface area (TSA) = 2(wl+hl+hw), where:

  • l = length
  • w = width
  • h = height of the box.

The amount of gift wrap needed to cover the whole box = total surface area of the rectangular box

l = 20 in.

w = 8 in.

h = 13 in.

Plug in the values into the formula for total surface area of a rectangular box:

TSA = 2(8×20 + 13×20 + 13×8)

TSA = 1,048 in.²

Therefore, the gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².

Learn more about rectangular box on:

brainly.com/question/13103197

6 0
1 year ago
Twice the quantity of a number plus two is greater than the number plus five.
Greeley [361]
2(x+2) > x+5
2x+4 > x+5
2x+4-x > x+5-x
x+4 > 5
x+4-4 > 5-4
x > 1
7 0
3 years ago
The circumference of a fountain is 63 feet. What is the approximate diameter?
Alik [6]

Answer:

Approximantly 20

Step-by-step explanation:

Circumference = pi times diameter

63/pi = diameter

Answer: 20.0535228

3 0
3 years ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
The angle measures 30°, 60°, 120°, and 150° are written on
GREYUIT [131]
Therefore the probability that the angle measure are supplementary are:120,60
8 0
3 years ago
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