Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
∠UXW = 36°
∠WZX = 66°
∠UWY = 48°
∠XYZ = 42°
Use the Alternate Exterior Angles Theorem. Always remember that a triangles angles add up 180°, so you can subtract the angles you already know in a triangle to figure out the remaining angle.
Answer:
Step-by-step explanation:
Let's start off with the first equation
5x + y = 60
We need to find what X and Y are.
Let's try subtracting a few numbers from 60.
Let's do 60 - 55 = 5
11x5 = 55
11 = Children Ticket Cost
5 = Seniors Ticket Cost
Without them being the same price!
So using the numbers we found, we can now solve the second one
14x5 = 70
11x11 = 121
70 + 121 = 191
There we go!
Hope this helped! Please give brainiest if you can :)
Answer:
see the explanation
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or 
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
Let
x ----> the time in hours
y ----> the distance in miles
<em>Find the value of k</em>
For the point (4,2268)

The slope represent the speed of the airplane
so
The linear equation is

Part 1 :
The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.
Part 2 :
The point (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours
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