All categories

3 years ago

Id appreciate some help ^^

Mathematics

2 answers:

Mrac [35]3 years ago

8 0

Answer:

392

Step-by-step explanation:

I would separate this into 2 shapes a triangle and a square. So first take the area of the square

area of square = base x height

16x19=304

Than take the area of the triangle

area of triangle = 1/2(base x height)

you can find the height of the triangle by subtracting 19 from 30 which is 11, and the base is the same as the base of the square which is 16

1/2(16x11)= 88

Add them together

304+88=392

bogdanovich [222]3 years ago

8 0

Answer: 392 in^2

Step by step solution: See photo

You might be interested in

a bicycle wheel has a diameter of 65cm what is the length of one revolution of the wheel PLEASE HELP

Lana71 [14]

AnswerAnswerAnswerAnswer: C = πd = 65π = 204.2 cm

Step-by-step explanation: C = pi*d

where d is the diameter.

First we get the circumference, then we multiply it by the number of revolutions, which is 20:

C = 3.14 * 65

C = 204.1 cm (this is only equal to 1 revolution)

Therefore, total distance travelled in after 20 revolutions is

204.1 * 20 = 4082 cm

7 0

2 years ago

Read 2 more answers

HELP PLEASE!!!! WILL GIVE 100 POINTS

Artist 52 [7]

Answer:

w to r to a

Step-by-step explanation:

e to c to p

8 0

3 years ago

Read 2 more answers

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

8-2x<4 solve inequality

Andreas93 [3]

Answer:

x > 2

x ∈ ( +2 ; + oo )

Step-by-step explanation:

8 - 2x < 4

8 - 4 < 2x

4 < 2x | : 2

2 < x

x > 2

x ∈ ( +2 ; + oo )

6 0

3 years ago

The map uses a scale of 1 in = 220 ft. On the map, how many inches represent 1 mile?

ASHA 777 [7]

Answer:

24 inches

Step-by-step explanation:

There are 5280 feet in a mile
There are 220 feet in 1 in on the map

5280/220 = 24

6 0

2 years ago