20 divided by 4 is 5 so
4$ will be for pay as you go.
5$ will be for regular deal
4+5=9 so the all in one deal is 9$
Answer:
A. $27.23
B. $467.77
Step-by-step explanation:
Lin is shopping for a couch with her dad and heard him ask the salesperson “how much is your commission?” The salesperson says that her commission is 5 1/2% of the selling price. A.How much commission will the salesperson earn by selling a couch for $495?
B.How much money will the store get from the sale of the couch?
Salesperson commission = 5 1/2%
Price of couch = $495
A. Amount earned by the salesperson = 5 1/2% of $495
= 5.5% × 495
= 0.055 × 495
= 27.225
Approximately
Amount earned by the salesperson = $27.23
B.How much money will the store get from the sale of the couch?
Amount the store get = Total price - amount earned by salesperson
= $495 - $27.23
= $467.77
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
I'm going to assume that the ' 7.51 ' is the angle expressed in radians.
So this is just like any other unit conversion exercise.
You know that 180 degrees = pi radians.
Divide each side by pi radians, and you have
180 degrees / pi radians = 1 .
Great ! Now take the angle you have ... 7.51 radians ...
and multiply it by ' 1 '.
(7.51 radians) x (180 degrees / pi radians) =
<em> </em> (7.51 x 180 / pi) degrees =<em> 430.29 degrees</em>
As you ( I ) worked through this problem, a very useful number
fell out . . . It's 180/pi = 57.296 , or just <em>57.3</em> is close enough.
Here's how you can use that number:
-- 1 radian = <u>57.3</u> degrees
-- 1 degree = 1/57.3 of a radian
-- Got some radians ? Multiply by <u>57.3</u> to get degrees.
-- Got some degrees ? Divide by <u>57.3</u> to get radians.
