<span>the general solution of the nonhomogenous differential equation </span><span>Y'' + 4y = t^(2) + 3e^t is c2y + c1</span>
4/5n – 1/5 = 2/5n
Add 1/5 to both sides
4/5n = 2/5n + 1/5
Subtract 2/5n from both sides
2/5n = 1/5
Divide both sides by 2/5
n = 1/2
Answer:
-20
Step-by-step explanation:
-20 divided by -4 is 5.