Question

Triangle A'B'C' is formed by a reflection over x = 1 and dilation by a scale factor of 2 from the origin. Which equation shows the correct relationship between AABC
and A'B'C'?

Answer 1

Answer:

$\frac{AB}{A"B"}=\frac{1}{2}$

Step-by-step explanation:

Given

$k = 2$ --- scale factor

Required

Relationship between ABC and A"B"C"

$k = 2$ implies that the sides of A"B"C" are bigger than ABC

i.e.

$A"B" = 2AB$

$A"C" = 2AC$

$B"C" = 2BC$

In $A"B" = 2AB$

Divide both sides by A"B"

$1 = \frac{2AB}{A"B"}$

Divide both sides by 2

$\frac{1}{2} = \frac{AB}{A"B"}$

Rewrite as:

$\frac{AB}{A"B"}=\frac{1}{2}$

(a) is correct