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xxTIMURxx [149]
2 years ago
15

Which point on the scatter plot is an outlier?

Mathematics
1 answer:
dlinn [17]2 years ago
7 0

Answer:

The point 9,50

Step-by-step explanation:

All the other ones are within a reasonable distance of each other.

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Whats the answer for 2x+3y=-13 <br><br> I would appreciate all of the work please and thank you
Artemon [7]

Answer: X=2 and y=3

Step-by-step explanation: 2x2=4 and 3x3=9 and 9+4=13

8 0
3 years ago
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In the past year Jenny watched 44 movies that she thought were very good. She watched 55 movies over the whole year. Of the movi
igomit [66]

To solve this problem, we must divide the number of movies that Jenny thought were very good by the total number of movies she watched. This is because we are finding a percentage, which represents a part out of a whole that have a factor, which in this case is very good movies. First, we begin by dividing 44/55. Then, we realize that both the numerator and the denominator are divisible by 11, so if we divided them both by 11 that would simplify the fraction.

44/55 = 44/11 / 55/11 = 4/5

Next, we can now easily divide our simplified fraction.

4/5 = 0.8

Finally, we must multiply by 100, because a percentage is a portion of 100 (the total is 100%). This is equivalent to moving the decimal point two places to the right.

0.8 * 100 = 80%

Therefore, Jenny thinks that 80% of the movies she watched this year were very good.

Hope this helps!

7 0
3 years ago
(2x2 – 18)(x+3)(2 – 3) = 2x4 – 36x2 + 162
lubasha [3.4K]

Answer:

X=4

Step-by-step explanation:

I'm took lazy to explain it step by step sorry, but I'm positive that's the correct answer.

6 0
3 years ago
Read 2 more answers
What is the measure of angle A?<br><br> A. 110<br> B. 70<br> C. 250<br> D. 55
zhuklara [117]
B. 70 is the correct answer
8 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
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