Answer: X=2 and y=3
Step-by-step explanation: 2x2=4 and 3x3=9 and 9+4=13
To solve this problem, we must divide the number of movies that Jenny thought were very good by the total number of movies she watched. This is because we are finding a percentage, which represents a part out of a whole that have a factor, which in this case is very good movies. First, we begin by dividing 44/55. Then, we realize that both the numerator and the denominator are divisible by 11, so if we divided them both by 11 that would simplify the fraction.
44/55 = 44/11 / 55/11 = 4/5
Next, we can now easily divide our simplified fraction.
4/5 = 0.8
Finally, we must multiply by 100, because a percentage is a portion of 100 (the total is 100%). This is equivalent to moving the decimal point two places to the right.
0.8 * 100 = 80%
Therefore, Jenny thinks that 80% of the movies she watched this year were very good.
Hope this helps!
Answer:
X=4
Step-by-step explanation:
I'm took lazy to explain it step by step sorry, but I'm positive that's the correct answer.
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.
Let's consider a simple example of estimating the value of a general definite integral,

Split up the interval
![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
into

equal subintervals,
![[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]](https://tex.z-dn.net/?f=%5Bx_0%2Cx_1%5D%5Ccup%5Bx_1%2Cx_2%5D%5Ccup%5Ccdots%5Ccup%5Bx_%7Bn-2%7D%2Cx_%7Bn-1%7D%5D%5Ccup%5Bx_%7Bn-1%7D%2Cx_n%5D)
where

and

. Each subinterval has measure (width)

.
Now denote the left- and right-endpoint approximations by

and

, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are

. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints,

.
So, you have


Now let

denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

Factoring out

and regrouping the terms, you have

which is equivalent to

and is the average of

and

.
So the trapezoidal approximation for your problem should be