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vekshin1
3 years ago
8

Help me pls I need it for my quiz​

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer:

тусын ыкс ыз ди ды жазып көр

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What does X equal??????????
tatuchka [14]

idk but I think its 30?

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Concert marketing: The college’s performing arts center wanted to investigate why ticket sales for the upcoming season significa
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Answer- a,b,d!!!! (i believe)
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A box contains plain pencils and 7 pens. A second box contains 6 colored pencils and 2 crayons. One item from each box is chosen
kondaur [170]

Answer:

it is 3 as a simplified fraction

Step-by-step explanation:

BOX 1) 5 plain pencils and 7 pens.  

BOX 2) 6 color pencils and 2 crayons.  

Plain pencil (first box) ~  5 : 7  

Color pencil (second box) ~ 6 : 2  

Simplify.  

3 : 1   <== Second box

3 0
2 years ago
Read 2 more answers
Which expression is a fourth root of -1+isqrt3?
aleksklad [387]

Answer:

Step-by-step explanation:

\sf n^{th} roots of a complex number is given by DeMoivre's formula.

   \sf \boxed{\bf r^{\frac{1}{n}}\left[Cos \dfrac{\theta + 2\pi k}{n}+i \ Sin \ \dfrac{\theta+2\pi k}{n}\right]}

Here, k lies between 0 and (n -1) ; n is the exponent.

\sf -1 + i\sqrt{3}

a = -1 and b = √3

\sf \boxed{r=\sqrt{a^2+b^2}} \ and \ \boxed{\theta = Tan^{-1} \ \dfrac{b}{a}}

\sf r = \sqrt{(-1)^2 + 3^2}\\\\ = \sqrt{1+9}\\\\=\sqrt{10}

                   \sf \theta = tan^{-1} \ \dfrac{\sqrt{3}}{-1}\\\\ = tan^{-1} \ (-\sqrt{3})

                   \sf = \dfrac{-\pi }{3}

n = 4

For k = 0,

          \sf z = \sqrt[4]{10}\left[Cos \ \dfrac{\dfrac{-\pi}{3} +0}{4}+iSin  \ \dfrac{\dfrac{-\pi}{3}+0}{4}\right] \\\\\\z= \sqrt[4]{10} \left[Cos \ \dfrac{ -\pi  }{12}+iSin  \ \dfrac{-\pi}{12}\right]\\\\\\z = \sqrt[4]{10}\left[-Cos \ \dfrac{\pi}{12}-i \ Sin \ \dfrac{\pi}{12}\right]

For k =1,

         \sf z = \sqrt[4]{10}\left[Cos \ \dfrac{5\pi}{12}+i \ Sin \ \dfrac{5\pi}{12}\right]

For k =2,

       z = \sqrt[4]{10}\left[Cos \ \dfrac{11\pi}{12}+i \ Sin \ \dfrac{11\pi}{12}\right]

For k = 3,

      \sf z = \sqrt[4]{10}\left[Cos \ \dfrac{17\pi}{12}+i \ Sin \ \dfrac{17\pi}{12}\right]

For k = 4,

      \sf z =\sqrt[4]{10}\left[Cos \ \dfrac{23\pi}{12}+i \ Sin \ \dfrac{23\pi}{12}\right]

4 0
2 years ago
Howdoyouwrite<br> 36/50<br> as a percentage?
DENIUS [597]

Answer:

72%

Step-by-step explanation:

Divide 36 by 50 to get .72, and then convert it to a percentage

8 0
3 years ago
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