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3 years ago

The circumference of a cylinder is 20 inches and the volume is 600 cubic inches. Calculate the height.

Mathematics

1 answer:

kipiarov [429]3 years ago

7 0

Answer:

h = 18.88 inches

Step-by-step explanation:

Given that,

The circumference of a cylinder is 20 inches

The volume of the cylinder, V = 600 cubic inches

We need to find the height of the cylinder. We know that the volume of a cylinder is given by :

$V=\pi r^2h$

r is radius

We know that,

circumference = 2πr

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{20}{2\pi}\\\\r=3.18\ \text{inches}$

So,

$h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{600}{\pi\times (3.18)^2}\\\\h=18.88\ \text{inches}$

So, the height of the cylinder is 18.88 inches.

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Harry created a canvas painting on a square canvas. He then placed an order for a new rectangular canvas. The side length of the

sveta [45]

Answer:

1.x^2

2.x+8

3.x

4. 8x

Step-by-step explanation:

Length of old is x inches.

Because it is square we have that area of the old canvas : $x^2$

When we read : width of new is increased by 8 so : x+8

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Now we can find A2-A1:

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3 years ago

The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

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Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi x^{3}$

For larger sphere: $Radius = 2x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$