The sum of two numbers is 40. The difference of those numbers is 8. Write a
1 answer:
Answer:
let two number be x and why
in 1st condition
x+y=40
x=40-y eqn (i)
in 2nd condition
x-y=8
x=8+y eqn (ii
now from eqn (i) and (ii)
40-y=8+y
32=2y
y=16
now putting the vale of why in eqn (i)
we get
x=40-16
=24
so two number are 24 and 16
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