Question

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Answer 1

Answer:

$\huge a)\frac{1}{ {3}^{9}. {6}^{18} }$

Step-by-step explanation:

to understand this

you need to know about:

• law of exponent
• PEMDAS

tips and formulas:

• ${x}^{ - y} < = > \frac{1}{ {x}^{y} }$
• $( {x} ^{z} )^{y} < = > {x}^{y \times z}$

let's solve:

$( {3}^{3} . {6}^{6} {)}^{ - 3}$

$\frac{1}{( {3}^{3}. {6}^{6} {)}^{3} }$

$\frac{1}{ {3}^{3 \times 3}. {6}^{6 \times 3} }$

$\frac{1}{ {3}^{9}. {6}^{18} }$