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VladimirAG [237]
3 years ago
10

How many 1/12pieces are in 3/3?

Mathematics
1 answer:
wel3 years ago
5 0

Answer:

plz ion know what is the awnser to mine

Step-by-step explanation:

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Please help my 10 year old nephew...
trasher [3.6K]

After, thorough research I believe that there are 265 pine trees and 0 elm trees since decidous and semi-decidous do not grow near conifers.

4 0
3 years ago
What are the x and y intercept for the graph of 4x - 3y = -12
Mama L [17]

Answer:

(-3,0) = x and (0,4) = y

Step-by-step explanation:

7 0
2 years ago
What are the possible values of x if (4c-5)^2= 49?
kykrilka [37]

Answer:

c = 3                              c = -1/2

Step-by-step explanation:

(4c-5)^2= 49

Take the square root of each side

sqrt((4c-5)^2)= ±qrt(49)

4c-5 = ±7

Separate into two equations

4c-5 = 7           4c-5 = -7

Add 5 to each side

4c-5+5 = 7+5          4c-5+5 =-7+5

4c =12                         4c = -2

Divide by 4

4c/4 = 12/4                     4c/4 = -2/4

c = 3                              c = -1/2

7 0
3 years ago
Read 2 more answers
An airplane is flying at 180mph. A jet flying at 330 mph leaves 1 hour later traveling in the same direction. How long will it t
zimovet [89]

To solve this problem, let us first assign some variables. Let us say that:

v1 = velocity of airplane = 180 mph

t1 = time travelled by airplane

v2 = velocity of jet = 330 mph

t2 = time travelled by jet

 

Since we know that distance is the product of velocity and time, and that the distance travelled by the two must be equal for the jet to catch up to the plane, hence:

v1 * t1 = v2 * t2

But we know that:

t1 = t2 + 1

Therefore:

180 (t2 + 1) = 330 t2

180 t2 + 180 = 330 t2

150 t2 = 180

t2 = 1.2 hours

 

<span>Therefore the jet can catch up to the plane after 1.2 hours it takes off.</span>

4 0
3 years ago
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0
3 years ago
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