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3 years ago

15

Rewrite the expression as a multiple of a sum of two numbers with no common factor 26 + 22

1 answer:

uysha [10]3 years ago

7 0

2(11+13) = 26+2w because 2(11)=22 2(13)=26

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3 years ago

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Simplify.Your answer should contain only positive exponents.

zhannawk [14.2K]

Step-by-step explanation:

1) $r^3r^3$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=r^{3+3}$

$=r^6$

2) $3k^3k^3$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=3k^{3+3}$

$=3k^6$

3) $\left(3b^2\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=3^3\left(b^2\right)^3$

$=27\left(b^2\right)^3$

$=27b^6$

4) $\left(2m^3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=2^3\left(m^3\right)^3$

$=8\left(m^3\right)^3$

$=8m^{3\cdot \:3}$

$=8m^9$

5) $\frac{3r^3}{r^2}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$=3r^{3-2}$

$=3r^1$

$=3r$

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3 years ago