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GrogVix [38]
3 years ago
15

Rewrite the expression as a multiple of a sum of two numbers with no common factor 26 + 22

Mathematics
1 answer:
uysha [10]3 years ago
7 0

2(11+13) = 26+2w because 2(11)=22 2(13)=26

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If B = w + 10 and C = -w - 1, find an expression that equals B + 2C in standard form
enot [183]

Answer:

Step-by-step explanation:

B + 2C

= w + 10 + 2(-w - 1)

= w + 10 -2w - 2

= -w + 8

8 0
3 years ago
Which expression is equivalent to the given expression?​
Whitepunk [10]

Answer:

4ln x +ln 3-lnx

4ln x -ln x+ln3

3ln x+ln 3

ln(3x+3)is equivalent.

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daeshon is in the math club. there are 21 students in the club. the math teacher will pick 2 students at random to guide visitin
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4 years ago
Alex borrowed $12.50 from his friend Danilo. He paid him back $8.75. How much does he still owe? *
ollegr [7]

Answer:

$3.75

Step-by-step explanation: $12.50

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8 0
3 years ago
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
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