I need to know if there functions or not (algebra)

Mathematics

1 answer:

faust18 [17]3 years ago

4 0

Answer:

Number 14 is a function and Number 16 is NOT a function.

Step-by-step explanation:

To check if a set of numbers form a function, you can look at the x values or the imput values.

For number 14 the x values are : 4,-3,-4,5,6. When looking at these values, there can only be one of each number.

For example in number 16, there's two 0's and we cannot allow that! So therefore, number 16 is not a function.

Also note, the y values are called the outputs.

A function is only allowed to have ONE imput with each output.

Hope this helps! :)

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10. Given matrices A, B, and C below, perform the indicated operations if possible. If the operation is not possible, explain wh

Artemon [7]

Answer(a):

Order of matrix A = 3x3 {because number of rows=3, number of columns=3}

Order of matrix B = 3x3

Order of matrix C = 1x3

3A will be of order 3x3 because multiply by scalar doesn't change the order. Which is same as the order of matrix B.

So 3A+B is possible.

We simply multiply all elements of A with 3 and add them with corresponding elements of B.

$3\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}+\begin{bmatrix}5 & 0& 2\\ 1 & -3& 9\\ 2 & 0& 4\end{bmatrix}= \begin{bmatrix}11 & -3& 2\\ 1 & 12& 9.9\\ 5 & 12& 34\end{bmatrix}$

Answer(b):

2B will be of order 3x3 because multiply by scalar doesn't change the order. Which is NOT same as the order of matrix C.

So 2B+C is NOT possible.

Answer(c):

CA is possible only if

number of columns of C = number of columns of A

3=3

which is true hence CA is possible.

$\begin{bmatrix}1 &3 &5 \end{bmatrix}*\begin{bmatrix}2 & -1& 0\\ 0 & 5& 0.3\\ 1 & 4&10 \end{bmatrix}=\begin{bmatrix}1*2+3*0+5*1 & 1*-1+3*5+5*4 & 1*0+3*0.3+5*10\end{bmatrix}$