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3 years ago

12

The median rainfall during a spring storm in the lowlands is about 4 mm less than a spring storm in the highlands. The mean rain

fall for the lowlands is about 3 mm less than for the highlands. Why is there a difference in the central measures for each data set?

2 answers:

Katen [24]3 years ago

6 0

The mean and the median are different because the data for the highlands has more variation than the data for the lowlands. The mean is affected by the outliers in the lowlands data.

butalik [34]3 years ago

3 0

Median is just the value that is neither the highest nor the lowest compared with the other values in the set

Mean is just the average of the numbers which is found out by adding up all the numbers then dividing the sum by the number of values in the set

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Y = 2x + 1 y = 3x - 1

yuradex [85]

Answer:

i think the answer is B

Step-by-step explanation:

5=6-1

5=5

6 0

2 years ago

Read 2 more answers

In 3 and 4, Classify each triangle by its sides and then by its angles

romanna [79]

Answer:

3. Sides: Equilateral

Angles: Acute

4. Sides: Isosceles

Angles: Right

Step-by-step explanation:

3. Sides: Equilateral because in an equilateral triangle all sides are equal.

Angles: Acute because in an acute triangle all angles are acute.

4. Sides: Isosceles because in an isosceles triangle two legs are equal.

Angles: Right because in a right triangle, one angle is right.

7 0

2 years ago

A password is 4 characters long and must consist of 3 letters and one number. if letters cannot be repeated and the password mus

sdas [7]

The possibility of selecting a 4 characters long password consisting of 3 letters and one number if letters cannot be repeated and the password must end with a number is 156000

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more number and variables.

The possibility of selecting the password = 26 * 25 * 24 * 10 = 156000

The possibility of selecting a 4 characters long password consisting of 3 letters and one number if letters cannot be repeated and the password must end with a number is 156000

Find out more on equation at: brainly.com/question/2972832

#SPJ4

7 0

1 year ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

B

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

C

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

D

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

E

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago

Analyze the diagram below and complete the instructions that follow. Find a, b, and c.

ahrayia [7]

Answer:

<u>The correct answer is the letter C. </u>

Step-by-step explanation:

We can use the following trigonometric identity:

$cos(60)=\frac{6}{b}$ (1)

$cos(45)=\frac{c}{b}$ (2)

Solving each equation by b and equaling we have:

$\frac{6}{cos(60)}=\frac{c}{cos(45)}$

$\frac{6}{cos(60)}=\frac{c}{cos(45)}$

Let's recall that:

$cos(45)=\frac{1}{\sqrt{2}}$

$cos(60)=\frac{1}{2}$

Then we have:

$c=\frac{cos(45)*6}{cos(60)}$

$c=\frac{2*6}{\sqrt{2}}$

$c=\frac{12}{\sqrt{2}}$

$c=6\sqrt{2}$

Using equation (1) we can find b.

$cos(60)=\frac{6}{b}$

$b=12$

Finally, we can find a using the next equation:

$tan(60)=\frac{a}{6}$

$a=6*tan(60)$

$a=6\sqrt{3}$

<u>Therefore, the correct answer is the letter C. </u>

I hope it helps you!

5 0

2 years ago