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liubo4ka [24]
2 years ago
6

I will make you brainiest!!! Help Fast!!!!!

Mathematics
1 answer:
erastova [34]2 years ago
8 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>

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What dimensions of the box are required to fit the candle? 5 cm by 6 cm by 18 cm 7 cm by 6 cm by 18 cm 5 cm by 3 cm by 18 cm 7 c
ella [17]

Answer:

7cm.by6cm sana makatulong

4 0
2 years ago
Read 2 more answers
Ill give brainliest - please help ASAP<br><br> WITH THE WORK THO PLEASE?
ohaa [14]

Answer:

5.

we have.

11x=½(16x+16+50)

22x=16x+66

22x-16x=66

6x=66

x=66/6

x=11

6.

118°=½(6x-11+181)

236=6x+170

6x=236-170

x=66/6

x=11°

7.

34°=½(arcAK-arc LN)

34×2=(110-arc LN)

arc LN =110-68

arc LN=42°

8.

<L=½(arc EN-arc KM)

<L=½(139°-73°)

<L=33

4 0
3 years ago
Solve the inequality and graph the solution set on a number line. Express the solution set in both​ set-builder and interval not
shusha [124]
<span>-8 < x -3 < 1
we have two inequations: 
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
*  x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
8 0
2 years ago
How do I solve this????
Arlecino [84]
Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater

so "b" is "4 more than 5 times" "a"

so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so       \bf \begin{cases}&#10;a+b=22\\&#10;--------------\\&#10;\boxed{b}=5a+4\qquad thus\\&#10;--------------\\&#10;a+\boxed{5a+4}=22&#10;\end{cases}

solve for "a", to see what the smaller one is

what's "b"?  well, b = 5a + 4
3 0
3 years ago
Is perpendicular to the line y = 2x + 1<br> and through the point (-1,5)
Monica [59]

Answer:

-2x+3

Step-by-step explanation:

Using y=mx+b

To make the line perpendicular, you just need to make the slope (m=2) negative. To make it go through (-1, 5), you just need to adjust the b value to raise the graph to a point where it will pass through the point.

4 0
3 years ago
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