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liubo4ka [24]
2 years ago
6

I will make you brainiest!!! Help Fast!!!!!

Mathematics
1 answer:
erastova [34]2 years ago
8 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>

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How do you do a flow proof?
nikdorinn [45]
I can talking a flow proof about geometry 
A flow proof is just one representational style for the logical steps that go into proving a theoremor other proposition; rather than progress read in two columns, as traditional proofs do flow proofs utilize boxes and linking arrows to show the structure or the argument.
5 0
2 years ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

A' = -512y^{-2} + 2

Set

A' = 0

This gives:

0 = -512y^{-2} + 2

Collect Like Terms

512y^{-2} = 2

Multiply through by y^2

y^2 * 512y^{-2} = 2 * y^2

512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

Width = y + 4

So:

Length = 8 + 2

Length = 10

Width = 16 + 4

Width = 20

To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0
2 years ago
Is this correct? Yes or no, and explain your answer.
Ilya [14]

Answer:

I think the answer you have is correct

Step-by-step explanation:

8 0
2 years ago
Simplify the expression.57 – 12 ÷ 4 • 3
JulsSmile [24]
Remember P.E.M.D.A.S

57 - 12 ÷ 4 · 3

= 57 - 3 · 3

= 57 - 9

= 48


7 0
3 years ago
If Professor Wilson found that the test scores of his students had a variance of 4.4, what is the standard deviation? Type a num
malfutka [58]

Answer:

The standard deviation will be: 2.1        

Step-by-step explanation:

We know that standard deviation is basically the square root of variance.

Using the formula to calculate the standard deviation

s=\sqrt{s^2}

As

  • The variance =  s² = 4.4

so the standard deviation can be calculated as:

standard deviation =\sqrt{s^2}

                                 =\sqrt{\left(4.4\right)^}

                                  =2.1

Therefore, the standard deviation will be: 2.1                      

8 0
3 years ago
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