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Anika [276]
3 years ago
5

A man walk for 2hr at 6km/h.he then cycled for a certain time at 16km/h.if he traveled 36km all together for how many hours did

he cycle
Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

t = 1.5 hours

Step-by-step explanation:

Given that,

A man walk for 2hr at 6 km/h.

He then cycled for a certain time at 16 km/h.

He travelled 36 km all together.

We need to find for how many hours did he cycle.

Distance walked in 2 hours = 2×6 = 12 km

Distance he cycled = 36-12 = 24 km

Let he cycled for t hours. So,

t=\dfrac{24}{16}\\\\t=1.5\ h

So, he cycles for 1.5 hours.

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Find the exponential function that passes through the points (2,80) and (5,5120)​
juin [17]

Answer:

  y = 5·4^x

Step-by-step explanation:

If you have two points, (x1, y1) and (x2, y2), whose relationship can be described by the exponential function ...

  y = a·b^x

you can find the values of 'a' and 'b' as follows.

Substitute the given points:

  y1 = a·b^(x1)

  y2 = a·b^(x1)

Divide the second equation by the first:

  y2/y1 = ((ab^(x2))/(ab^(x1)) = b^(x2 -x1)

Take the inverse power (root):

  (y2/y1)^(1/(x2 -x1) = b

Use this value of 'b' to find 'a'. Here, we have solved the first equation for 'a'.

  a = y1/(b^(x1))

In summary:

  • b = (y2/y1)^(1/(x2 -x1))
  • a = y1·b^(-x1)

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For the problem at hand, (x1, y1) = (2, 80) and (x2, y2) = (5, 5120).

  b = (5120/80)^(1/(5-2)) = ∛64 = 4

  a = 80·4^(-2) = 80/16 = 5

The exponential function is ...

  y = 5·4^x

3 0
3 years ago
1/4 + 5/8 + 1/8 + 1/4 + 1/4 + 1/4 + 3/4 + 3/4
zysi [14]
1/4=2/8  and 3/4=6/8... common denominator 
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7 0
3 years ago
Read 2 more answers
Helen wrote and solved the equation.
Savatey [412]

Answer:

b, Helen should have added 17 to both sides of the equation

Step-by-step explanation:

just took quiz and got it right so it will help u guys too.!!!

7 0
3 years ago
Read 2 more answers
A family is comparing different car seats. One car seat is designed for a child up to and including 30 lb. Another car seat is d
mixer [17]
The number lines should show the weights the car seats are designed for in comparison the the weight of the 32lb child. The car seat made for children 30lb and lighter would not work because this child is 32lbs. Model this by placing a filled in circle at 30 and the arrow should face left. The seat for children between 15lbs and 40lbs and the seat designed for a child that is between 30lbs and 85lbs would work because the child is within these weight ranges. The number line for the seat for a 15lb-40lb child would have open circles at 15 and 40 with a line connecting the two points. The number line for a 30lb-85lb child should have filled in circles at these two point with a line connecting them.
6 0
3 years ago
Tickets at a play cost $10 or $14. If 800 tickets were sold and $9,040 was collected by the box office, how many $14 tickets wer
pav-90 [236]
STEP 1:
determine equations needed

x= # of $10 tickets
y= # of $14 tickets

QUANTITY EQUATION
x + y= 800

COST EQUATION
$10x + $14y= $9,040


STEP 2:
multiply quantity equation by -14

-14(x + y)= -14(800)
-14x - 14y= -11,200


STEP 3:
add new quantity equation in step 2 to cost equation of step 1 to solve for x using elimination

-14x - 14y= -11,200
10x + 14y= 9040
y term cancels out

-4x= -2160
divide both sides by -4

x= 540 ten dollar tickets


STEP 4:
substitute x value in step 3 into either original equation

x + y= 800
540 + y= 800
subtract 540 from both sides

y= 260 fourteen dollar tickets


ANSWER: There were 540 $10 tickets and 260 $14 tickets sold.

Hope this helps! :)
5 0
3 years ago
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