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RideAnS [48]
3 years ago
11

A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A random sample

of 18 sophomores is surveyed and asked whether they support the school adopting uniforms, and three students said yes. The student wants to construct a 95% confidence interval for the proportion of sophomores who favored the adoption of uniforms. Are the conditions for inference met
Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

Option D

Step-by-step explanation:

Complete question

A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A random sample of 18 sophomores is surveyed and asked whether they support the school adopting uniforms, and three students said yes. The student wants to construct a 95% confidence interval for the proportion of sophomores who favor the adoption of uniforms. Are the conditions for inference met?

  1. Yes, the conditions for inference are met.
  2. No, the 10% condition is not met.  
  3. No, the randomness condition is not met.  
  4. No, the Large Counts Condition is not met.

Solution

10 % of population size of 200 is 20. The sample of 18 is smaller than the 10 % of sample size of 200. As per the 10% rule, the size of sample must be less than 10% of the total size of population. This indicate that the sample is random but its size is less that 30. However, it should be greater that 30. Hence, the large count condition is not met.

Hence, option D is the correct choice of answer

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Yuri [45]

Step-by-step explanation:

Distance between Train 1 and Train 2=95 miles

Avg speed Train 1 = 45mph, avg speed Train 2=60mph

If both trains leave at the same time and travel toward each other but on parallel tracks, in how much time will their engines be opposite each other?

:

Let t = travel time (in hrs) until they are opposite each other

:

Like the hint said, when this happens the total distance traveled by both trains will be 95 mi.

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write a distance equation from this fact: Dist = speed * time

;

Train 1 dist + train 2 dist = 95 mi

45t + 60t = 95

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105t = 95

t = 95%2F105

t = .90476 hrs

or

.90476 * 60 = 54.3 min

:

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Check solution by finding the total of the distances the two train travel

45(.90476) + 60(.90476) =

40.7 + 54.3 = 95 mi

6 0
3 years ago
A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
ddd [48]

Answer:

Mean = 15.15

Standard deviation = 0.6062

Step-by-step explanation:

We are given a uniform distribution of  quantity to be put in each bag.

Low and high filling weights:

14.1 pounds and 16.2 pounds

a = 14.1

b = 16.2

a) Mean:

\mu = \displaystyle\frac{a+b}{2}\\\\\mu = \frac{14.1+16.2}{2} = 15.15

b) Standard Deviation:

\sigma = \sqrt{\displaystyle\frac{(b-a)^2}{12}}\\\\= \sqrt{\dfrac{(16.2-14.1)^2}{12}} = \sqrt{0.3675} = 0.6062

4 0
3 years ago
Respuesta para 8×-2=-9+7×
den301095 [7]
The answer is x=-7
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3 years ago
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brilliants [131]

Answer:

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Step-by-step explanation:

She pays 18 dollars each moth, therefore that quantity won't change, so you will have to add. Each movie that she watches is an additional 3.50, then we have 3.50 x, x being the quantity of movies that she watches. She can only afford up to 40 dollars, then everything that she spends has to be less or equal to 40.

8 0
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ludmilkaskok [199]
600÷30= 20
20 millimeters per minute
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3 years ago
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