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slamgirl [31]
2 years ago
10

Factor this problem and then use the Zero Product property to get the two solutions 6x²-23x+20

Mathematics
1 answer:
Leni [432]2 years ago
6 0

Answer:

(3x-4) x (2x-5)

Step-by-step explanation:

(3x-4)= x=12. ( 2x-5)= 10. x=10

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Michael is buying a pair of jeans that regularly cost $40. They are on sale for 20% off. If the tax rate is 8%, what is the sale
Anna35 [415]

Answer      

Find out the  what is the sale price of the jeans including tax .

To prove

Let us assume that the sale price of the jeans including tax be x .

As given

Michael is buying a pair of jeans that regularly cost $40.

They are on sale for 20% off.

If the tax rate is 8% .

20% is written in the decimal form

= \frac{20}{100}

= 0.20

8% is written in the decimal form

= \frac{8}{100}

= 0.08

Than the equation becomes

x = 40 - 40 × 0.20 + 40 × 0.08

x = 40 - 8 + 3.2

x = 43.2 - 8

x = $35.2

Therefore the sale price of the jeans including tax be $ 35.2 .



4 0
3 years ago
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
give me answers for the blank parts please ive been trying this for at least 15 minutes and i swear i will get in so much troubl
DIA [1.3K]

Answer:

4 , 1 and 6

Step-by-step explanation:

now ur not in trouble :)

7 0
3 years ago
Two sides of a triangle measure 9 cm and 23 cm Which could be the measure of the
Irina-Kira [14]
Is this multiple choice?
8 0
3 years ago
higher order thinking shailen is adding three numbers he gets a sum that is an even number between 10 and 20 show two addition e
nika2105 [10]

18: 15+2+1=18

18: 12+3+3=18


4 0
3 years ago
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