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Lisa [10]
3 years ago
12

What is the answer to 4+4-(5-1)

Mathematics
1 answer:
Zanzabum3 years ago
6 0
Your answer would be 4 you go with P.E.M.D.A.S so (5-1)= 4 then 4+4=8-4=4
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Anderson Systems is considering a project that has the following cash flow and WACC data. What is the project's NPV? Note that i
AURORKA [14]

Answer:

$265.65

Step-by-step explanation:

Given :

WACC: 9.00%

Year 0 1 2 3 Cash flows (-$1,000) $500 $500 $500

The NPV is calculated thus :

Initial cashflow + Σ additional cash flows / (1 + r)

Rate, r = 9% = 0.09

(1 + r) = (1 + 0.09) = 1.09

NPV = - 1000 + (500 / (1.09)¹ + (500 / 1.09)² + (500 / (1.09)³

NPV = - 1000 + 458.71559 + 420.83999 + 386.09174

NPV = 265.64732

NPV = 265.65 (2 DECIMAL PLACES)

5 0
3 years ago
What is the value of the digit 9 in 71.92​
Alik [6]

Answer:

.90

Step-by-step explanation:

?

4 0
2 years ago
What is the value of t?
valina [46]

Answer:

54

Step-by-step explanation:

comment if you want a step-by-step

5 0
2 years ago
In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the pro
postnew [5]

Answer:

The probability that more than half of them have Type A blood in the sample of 8 randomly chosen donors is P(X>4)=0.1738.

Step-by-step explanation:

This can be modeled as a binomial random variable with n=8 and p=0.4.

The probability that k individuals in the sample have Type A blood can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.4^{k} 0.6^{8-k}\\\\\\

Then, we can calculate the probability that more than 8/2=4 have Type A blood as:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\\\P(x=5) = \dbinom{8}{5} p^{5}(1-p)^{3}=56*0.0102*0.216=0.1239\\\\\\P(x=6) = \dbinom{8}{6} p^{6}(1-p)^{2}=28*0.0041*0.36=0.0413\\\\\\P(x=7) = \dbinom{8}{7} p^{7}(1-p)^{1}=8*0.0016*0.6=0.0079\\\\\\P(x=8) = \dbinom{8}{8} p^{8}(1-p)^{0}=1*0.0007*1=0.0007\\\\\\\\P(X>4)=0.1239+0.0413+0.0079+0.0007=0.1738

3 0
3 years ago
Analyses were run. The following is the (edited) output for the test:
ArbitrLikvidat [17]

Answer: C. The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread fo home games is higher than that of away games.

Step-by-step explanation: In Hypothesis Testing using p-value, after stating the null an alternative hypothesis, you have to compare p-value with level of significance, also known as α. If p-value is less than α, reject null hypothesis and accept alternative. If p-value is bigger, we would fail to reject null hypothesis and not accept the alternative.

In the above testing, P-value is 0.4351. Level of significance is, generally, 0.05. Comparing them, p-value is bigger than α. What it means is there is not enough evidence to support null hypothesis and, consequently, we can't conclude the difference in mean point spread of home games is higher than of the away games.

8 0
3 years ago
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