Caution: you need to use the same units of measurement throughout. If the spring stretches by 21 cm when a 135 newton object is attached, then you must ask for the mass (in newtons) of a fish that would stretch the spring by 62.1 cm.
We will need to assume that the spring is not stretched at all if and when no object is attached to the spring.
Write the ratio
21.0 cm 135 newtons
------------- = --------------------
62.1 cm x
Solve this for x. This x value represents the mass of a fish that would stretch the spring by 62.1 cm. You can cancel "cm" in the equation above:
21.0 135 newtons
------ = --------------------
62.1 x
Then 21.0x = (62.1)(135 newtons). Divide both sides of this equation by 21.0 to solve it for x.
Answer:
Step-by-step explanation:
given data;
B = 16m
b =8 m
height H = 4 m
length L = 32 m
volume of any right cylinder = (Area of bottom) \times (length)
Volume = A* L
The area of a trapezoid is
therefore volume is given as
volume = 48*32
Answer:
Step-by-step explanation:
1. Approach,
For this problem, the format of a line that will be used is, slope-intercept form;
Where (
) is the slope of the line, also known as the change in the line and 
is the y-intercept, or where the graph of the line intersects the y-axis. Since, in this problem, the slope of the line is given, all one has to do is substitute in a point on the given line and solve.
2. Finding the equation,
In this problem, the slope of the line is given. Therefore, to solve this problem, all one has to do is substitute in a point on the given line and solve.
Substitute in the slope,
Substitute in the point,
Simplify,
Inverse operations,
3. Putting it all together,
Now, that one has y-intercept, (
); use the given slope and the formula , substitute in all the information.
Answer:
9
Step-by-step explanation:
sqrt(5) + sqrt(405)
sqrt(5) + sqrt( 81*5)
sqrt(5) + sqrt(81) sqrt(5)
sqrt(5) +9 sqrt(5)
10 sqrt(5)
Arc PR is 156 degrees. Since both angles are are making the forming arc they should be congruent. You can put (5x+23)=(9x-21) which is x=11.
Then you plug in 11 into your equation; 5(11)+23=78.
Since the vertex is on the outside of the circle then the arc is forms is 2 times the value of the angle.
78(2)=156
