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daser333 [38]
3 years ago
9

2p^2+10=0 Please help!

Mathematics
1 answer:
ohaa [14]3 years ago
7 0
2p^2+10=0\ \ \ |-10\\\\2p^2=-10\ \ \ |:2\\\\p^2=-5
No real solutions, because for all real numbers the square of number is greater or equal 0.


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What does it mean if the distance between a point p and a line l is zero? What does it mean if the distance between two lines is
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Answer:

a) the point is on the line

b) the lines are the same line

Step-by-step explanation:

a) The distance from a point to a line is zero when the point satisfies the equation of the line. That is, the point is on the line.

b) Two lines are zero distance apart when they are on top of each other, indistinguishable. That is, they are the same line.

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3 years ago
Graham puts $20 in his piggy bank every week. At the end of 39 weeks, he adds $100 to the piggy bank money and decides to do the
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147.59 is the total amount given to each brother after all purchases were made.
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Consider the following function:y=1/(x+5)+2
Galina-37 [17]

Answer:

Step-by-step explanation:

Starting with the parent function, x was replaced by (x + 5), indicating that the graph of the new function is that of the old function shifted 5 units to the LEFT.  That +2 shifts this result UP by 2 units.

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3 years ago
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Which expression shows 48+36 written as a protuct of two factors
nirvana33 [79]

Answer:

12(4+3)

Step-by-step explanation:

Factor out all of the problems.

Starting with 4(12+4)

This means (4*12)+(4*4)

48+16 is the answer to this

this isn't 48 + 36

12(4+3) is next

12*4 = 48

12*3 = 36

48+36 = 48 + 36

Therefore 12(4+3) is your answer

hope that helps!

hope this is what your looking for

8 0
2 years ago
(4x^2y^3+2xy^2-2y)-(-7x^2y^3+6xy^2-2y)
Rasek [7]

Answer:

x y^2 (11 x y - 4)

Step-by-step explanation:

Simplify the following:

4 x^2 y^3 + 2 x y^2 - 2 y - (-7 x^2 y^3 + 6 x y^2 - 2 y)

Factor y out of -7 x^2 y^3 + 6 x y^2 - 2 y:

4 x^2 y^3 + 2 x y^2 - 2 y - y (-7 x^2 y^2 + 6 x y - 2)

-y (-2 + 6 x y - 7 x^2 y^2) = 2 y - 6 x y^2 + 7 x^2 y^3:

4 x^2 y^3 + 2 x y^2 - 2 y + 2 y - 6 x y^2 + 7 x^2 y^3

Grouping like terms, 4 x^2 y^3 + 2 x y^2 - 2 y + 2 y - 6 x y^2 + 7 x^2 y^3 = (4 x^2 y^3 + 7 x^2 y^3) + (2 x y^2 - 6 x y^2) + (2 y - 2 y):

(4 x^2 y^3 + 7 x^2 y^3) + (2 x y^2 - 6 x y^2) + (2 y - 2 y)

x^2 y^3 4 + x^2 y^3 7 = 11 x^2 y^3:

11 x^2 y^3 + (2 x y^2 - 6 x y^2) + (2 y - 2 y)

x y^2 2 + x y^2 (-6) = -4 x y^2:

11 x^2 y^3 + -4 x y^2 + (2 y - 2 y)

2 y - 2 y = 0:

11 x^2 y^3 - 4 x y^2

Factor x y^2 out of 11 x^2 y^3 - 4 x y^2:

Answer:  x y^2 (11 x y - 4)

7 0
3 years ago
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