Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

Hence the bounds of the interval are:
As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
Volume = (24x⁵ + 78x⁴ - 147x³ - 624x² - 360x)
Step-by-step explanation:
Container given in the picture is in the shape of a cuboid.
And volume of a cuboid is measured by the expression,
Volume of a cuboid = Length × width × height
Now substitute the measure of the container's dimensions given in the picture
Volume = (4x² + 3x)(x²- 8)(6x + 15)
= [(4x² + 3x)(x²- 8)](6x + 15)
= [4x²(x² - 8) + 3x(x² - 8)](6x + 15)
= (4x⁴ - 32x² + 3x³ - 24x)(6x + 15)
= (4x⁴ + 3x³ - 32x² - 24x)(6x + 15)
= 6x(4x⁴ + 3x³ - 32x² - 24x) + 15(4x⁴ + 3x³ - 32x² - 24x)
= 24x⁵+ 18x⁴ - 192x³ - 144x² + 60x⁴ + 45x³ - 480x² - 360x
= 24x⁵ + 78x⁴ - 147x³ - 624x² - 360x
Flip about the y-axis, move it up 7 spaces.
Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
Answer:
21 projects each
Step-by-step explanation:
3150 ÷150