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3 years ago

Which three side lengths best describe the triangle in the diagram?

Mathematics

1 answer:

dimaraw [331]3 years ago

4 0

Answer:

A. can I come anwser my question

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Calculate the distance between the points K = (1, -1) and P=(9.-6) in the coordinate plane.

GarryVolchara [31]

Answer:

√89

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(9 - 1)² + [-6 - (-1)]²

√(8)² + (-5)²

√64 + 25

√89

6 0

3 years ago

A group of engineers is building a parabolic satellite dish whose shape will be formed by rotating the curve y=ax 2 about the y-

Setler79 [48]

Answer:

a = $\frac{1}{2}$ . Surface Area = $\frac{4}{3}$ $ft^{2}$ . and area of the Dish = $\frac{4}{3}$ $ft^{2}$ +pi $4^{2}$ = $\frac{4}{3}$ $ft^{2}$ +50.27=51.6 $ft^{2}$

Step-by-step explanation:

(1) Constant. y(x) = a $x^{2}$ that is the curve that we need to rotate around the y axis to get the parabola with diameter of 8 feet and 2 meter depth that statement is translated in mathematics as x = -4 to 4 and y = 0 to 2.

y max = 2, x max = 4 setting up a equation with a unknown gives

2=a4 and a = $\frac{1}{2}$ .

so we have now.

y(x) = $\frac{1}{2}x^{2}$ (Done with solving for a Constant).

(2) Surface Area.

Setting Up surface integral.

(i) range in x = 0 to 4.

(ii) range in y = 0 to 2.

integral is.

Integral(0-2)[{integral[(0-4) $\frac{1}{32}$ $x^{2}$ ]}]dy

Evaluating this integral gives. $\frac{4}{3}$ $ft^{2}$ .

and area is surface area + area of the circle with 8ft diameter.

= $\frac{4}{3}$ $ft^{2}$ +pi $4^{2}$ = $\frac{4}{3}$ $ft^{2}$ +50.27=51.6 $ft^{2}$ ...

Note the Difference between area and aurface area.!

6 0

3 years ago

What is M ∠KNL ? Circles

alex41 [277]

Answer:

Do you still need help with this problem?

5 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

4 years ago

Find a number whose 6 1/4% is 12

Pachacha [2.7K]

Answer: The number is 192

Step-by-step explanation:

8 0

3 years ago