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3 years ago

9

The ratio of red marbles to blue marbles is 3:5. If there are 360 marbles total in the collection, how many of each color are th

ere?

2 answers:

kari74 [83]3 years ago

8 0

Answer:

135 red and 225 blue

Step-by-step explanation:

Ber [7]3 years ago

3 0

What they said
Skjsoakakakao

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The corresponding sides of ΔABC and ΔDEF have equal lengths. The area of ΔABC is 4 square units, and the longest side of ΔDEF is

lisabon 2012 [21]

Answer:

4 square units

Step-by-step explanation:

If the triangles have corresponding sides the same length, they are congruent triangles. Any measure of ΔABC is the same for ΔDEF.

The area of ΔDEF is 4 square units.

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2 years ago

Indicate the method you would use to prove the two 's . If no method applies, enter "none".

Andrei [34K]

Answer: ASA method must be applied to the given triangles to prove then congruent.

In two triangles, if two angles and their included side are congruent then the two triangles are said to be congruent .This method is known as Angle-Side -Angle postulate(ASA).
In the given triangles one side with their corresponding angles are equal. Therefore by ASA postulate they are congruent.
There we can see no other sides are given equal therefore all the other options cannot be applied.

you are lucky I had this test yesterday and I have the answer is ASA my math teacher said it was fine

6 0

3 years ago

Warmup/Reflection- necessary for attendance

Pepsi [2]

Answer:

x = 7

Step-by-step explanation:

-3 + 2x = 11

(group like terms)

2x = 11 + 3

2x = 14

(divide both sides by 2 to make x stand alone)

2x/2 = 14/2

x = 7

8 0

3 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

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3 years ago

A rectangle is inscribed in the region bounded by the x-axis, the y-axis, and the graph of x+2y-8=0. Approximate the dimensions

Rasek [7]

Hope this helps you.

4 0

3 years ago