I think its 0 hope I helped
Answer: d. .2474.
Step-by-step explanation:
Given : The cashier service time at the local branch of the Rivertown bank has an exponential distribution with a mean of 2.5 minutes.
The cumulative distribution function for exponential distribution is :-
, where
= Mean of the distribution.
The probability that the service time is between 2 and 4 minutes will be :
![P(2\leq X \leq 4)=P(X\leq4)-P(X\leq 2)\\\\= (1-e^{\frac{-4}{2.5}})-(1-e^{\frac{-2}{2.5}})\\\\=e^{\frac{-2}{2.5}}-e^{\frac{-4}{2.5}}\\\\=0.449328964117-0.201896517995\\\\=0.247432446123\approx0.2474](https://tex.z-dn.net/?f=P%282%5Cleq%20X%20%5Cleq%204%29%3DP%28X%5Cleq4%29-P%28X%5Cleq%202%29%5C%5C%5C%5C%3D%20%281-e%5E%7B%5Cfrac%7B-4%7D%7B2.5%7D%7D%29-%281-e%5E%7B%5Cfrac%7B-2%7D%7B2.5%7D%7D%29%5C%5C%5C%5C%3De%5E%7B%5Cfrac%7B-2%7D%7B2.5%7D%7D-e%5E%7B%5Cfrac%7B-4%7D%7B2.5%7D%7D%5C%5C%5C%5C%3D0.449328964117-0.201896517995%5C%5C%5C%5C%3D0.247432446123%5Capprox0.2474)
Hence, the correct option is d. .2474.
<span>p ← 1
s ← 0
for i is in {1, 2, 3, 4}
do p ← p · 3
s ← s + p
n = 1 => first iteration
p = 1 * 3 = 3
s = 0 + 3 = 3
number of multiplications ---> 1
n = 2
p = 3 * 3 = 9
s = 3 + 9 = 12
number of multiplications ----> 1 + 1 = 2
n = 3
p = 9 * 3 = 27
s = 12 + 27 = 39
number o multiplications --> 2 + 1 = 3
n = 4
p = 27 * 7 = 81
s = 39 + 81 = 120
final number of multiplications -----> 3 + 1 = 4
final value of s
s = 120
Answer: number of mujltiplications: 4
final value of s: s = 120.
</span>
3(2x-6)+x
6x-18+x
7x-18
is the answer