Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
Answer:
Step-by-step explanation:
x-the original price
y- the discounted price
y= the original price - 25 % discounted from x = x- (.25*x) = x( 1-.25) = .75x
equation is y= .75x
The equation should only be in the first quadrant because the prices can only be positive numbers.
Yes the trip is worthwhile. If you save $50, but it takes you $10 in gas o get theready & $10 in gas to get back you still have $30 saved.
Answer:
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Answer: -2v-20
Step-by-step explanation: -2 times v is -2v
and -10 times -2 is -20.
