Check the picture below.
so is really just a thick trapezoid, or namely a trapezoidal prism 5 inches thick.
so if we just get the area of the trapezoidal face and multiply by the thickness, we'd get it's volume
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{parallel~sides}{bases}\\ h=height\\[-0.5em] \hrulefill\\ a = 8\\ b = 13\\ h = 6 \end{cases}\implies A=\cfrac{6(8+13)}{2}\implies A=63 \\\\\\ \stackrel{\textit{area of the trapezoidal prism}}{63\cdot 5\implies \stackrel{in^3}{315}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%20%3D%208%5C%5C%20b%20%3D%2013%5C%5C%20h%20%3D%206%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B6%288%2B13%29%7D%7B2%7D%5Cimplies%20A%3D63%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20trapezoidal%20prism%7D%7D%7B63%5Ccdot%205%5Cimplies%20%5Cstackrel%7Bin%5E3%7D%7B315%7D%7D)
9.8(k+9)−5.7
Distribute:
=(9.8)(k)+(9.8)(9)+−5.7
=9.8k+88.2+−5.7
Combine Like Terms:
=9.8k+88.2+−5.7
=(9.8k)+(88.2+−5.7)
=9.8k+82.5
Answer:
=9.8k+82.5
The distance between point C and point D is 10.
Point D is on the 1 and Point C is on -9.
1-(-9)=10.
Answer:
y=-1/2x+80
Step-by-step explanation:
Answer:
ok so the graph tells you 24 seconds by 4 ounces
Step-by-step explanation:
The point where both lines meet is the point where they are both equal.
The point where both lines meet is (24,4)
Since the x-axis represents seconds the x-coordinate will represent the number of seconds it takes for them to be equal which is 24.
Since the y-axis represents ounces the y-coordinate will represent the number of ounces they have when they are equal which is 4.