Answer:
Is it the full question I mean what does it want next anyway?
But here's your answer :
3x^4 + 14x^3 + 23x^2 + 16x + 4
The answer is mostly likely B
Answer: here are a few ordered pairs
1. (0,-4)
2.(8,0)
3.(16,4)
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
