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DedPeter [7]
3 years ago
7

3. Solve for x. (x-2)(x+ 8) = 0

Mathematics
1 answer:
docker41 [41]3 years ago
8 0

Answer:

x = 2, x = -8

Step-by-step explanation:

Since the equation equals 0, you know either (x-2) or (x+8) has to equal 0.

This means x = 2, and x = -8

Hope this helps!

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Please help..................
oksano4ka [1.4K]

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Step-by-step explanation:

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8 0
3 years ago
Graph the function f(x)=x2.
grandymaker [24]

Graph f(x) = x^2

quadratic function is of the form f(x) = ax^2 + bx +c

In our f(x) there is no x term and constant so we put 0

f(x) = 1x^2+0x+0

The value of a=1 , b=0  and c=0

To find vertex , use formula x= \frac{-b}{2a}

Plug in the values

x= \frac{-0}{2(1)} =0

Now plug in x=0 in f(x) equation

f(x) = x^2

f(0) = 0^2=0

So vertex is (0,0)

Now we pick some number for x below and above 0

Make a table

x            y=x^2

-2           4

0             0

2            4

Now plot all the points (-2,4) (0,0) and (2,4)

The graph is attached below


7 0
3 years ago
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