In ΔQRS, q = 890 cm, s = 810 cm and ∠S=120°. Find all possible values of ∠Q, to the nearest degree.

Identify the restrictions on the domain of f(x) = quantity x plus 5 over quantity x minus 2. x ≠ 5 x ≠ −5 x ≠ 2 x ≠ −2

horsena [70]

Answer: Third option.

Step-by-step explanation:

By definition, Rational Functions have the following form:

$f(x)=\frac{P(x)}{Q(x)}$

Where $P(x)$ and $Q(x)$ are polynomials.

The Restrictions of the Domain of Rational Functions are those Real numbers that make the denominator equal to zero, because the division by zero is not defined.

In this case, you have the following Rational Function:

$f(x)=\frac{x+5}{x-2}$

The Restrictions of the Domain can be found applying this steps:

- Make the denominator equal to 0:

$x-2=0$

- Solve for "x":

$x=2$

Then, the Domain of this function includes all "x" not equal to 2.

Therefore, the answer is:

$x\neq 2$

8 0

3 years ago

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$

$X - 35000 = -1.88*7000$

$X = 21840$

The designed life should be of 21,840 vehicle miles.

3 0

2 years ago

An office manager needs to decide between two tables for the conference room. One is rectangular, 5 feet wide by 10 feet long. T

7nadin3 [17]

Answer:

The rectangular 5 x 10 table.

Step-by-step explanation:

To find which table the office manager needs to get so he can sit more people at it is decided by one factor, the perimeter. The rectangular one, which is 5 x 10 the perimeter is (5 x 2) + (10 x 2) = 10 + 20 = 30. The circular one can be calculated by the equation $\pi * d$ where d = 8. Putting $/pi$ x 8 in my calculator and it comes out approximately at 25.132, having a less amount of perimeter space to work with, making the rectangular table the way to go.